Integrand size = 17, antiderivative size = 41 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=\frac {(1+x)^{3/2}}{5 (1-x)^{5/2}}+\frac {(1+x)^{3/2}}{15 (1-x)^{3/2}} \]
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Time = 0.00 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {47, 37} \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=\frac {(x+1)^{3/2}}{15 (1-x)^{3/2}}+\frac {(x+1)^{3/2}}{5 (1-x)^{5/2}} \]
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Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = \frac {(1+x)^{3/2}}{5 (1-x)^{5/2}}+\frac {1}{5} \int \frac {\sqrt {1+x}}{(1-x)^{5/2}} \, dx \\ & = \frac {(1+x)^{3/2}}{5 (1-x)^{5/2}}+\frac {(1+x)^{3/2}}{15 (1-x)^{3/2}} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.61 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=\frac {(4-x) (1+x)^{3/2}}{15 (1-x)^{5/2}} \]
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Time = 0.16 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.44
method | result | size |
gosper | \(-\frac {\left (x -4\right ) \left (1+x \right )^{\frac {3}{2}}}{15 \left (1-x \right )^{\frac {5}{2}}}\) | \(18\) |
default | \(\frac {2 \sqrt {1+x}}{5 \left (1-x \right )^{\frac {5}{2}}}-\frac {\sqrt {1+x}}{15 \left (1-x \right )^{\frac {3}{2}}}-\frac {\sqrt {1+x}}{15 \sqrt {1-x}}\) | \(44\) |
risch | \(-\frac {\sqrt {\left (1+x \right ) \left (1-x \right )}\, \left (x^{3}-2 x^{2}-7 x -4\right )}{15 \sqrt {1-x}\, \sqrt {1+x}\, \left (-1+x \right )^{2} \sqrt {-\left (-1+x \right ) \left (1+x \right )}}\) | \(54\) |
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none
Time = 0.22 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.29 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=\frac {4 \, x^{3} - 12 \, x^{2} + {\left (x^{2} - 3 \, x - 4\right )} \sqrt {x + 1} \sqrt {-x + 1} + 12 \, x - 4}{15 \, {\left (x^{3} - 3 \, x^{2} + 3 \, x - 1\right )}} \]
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Result contains complex when optimal does not.
Time = 6.41 (sec) , antiderivative size = 172, normalized size of antiderivative = 4.20 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=\begin {cases} \frac {i \left (x + 1\right )^{\frac {5}{2}}}{15 \sqrt {x - 1} \left (x + 1\right )^{2} - 60 \sqrt {x - 1} \left (x + 1\right ) + 60 \sqrt {x - 1}} - \frac {5 i \left (x + 1\right )^{\frac {3}{2}}}{15 \sqrt {x - 1} \left (x + 1\right )^{2} - 60 \sqrt {x - 1} \left (x + 1\right ) + 60 \sqrt {x - 1}} & \text {for}\: \left |{x + 1}\right | > 2 \\- \frac {\left (x + 1\right )^{\frac {5}{2}}}{15 \sqrt {1 - x} \left (x + 1\right )^{2} - 60 \sqrt {1 - x} \left (x + 1\right ) + 60 \sqrt {1 - x}} + \frac {5 \left (x + 1\right )^{\frac {3}{2}}}{15 \sqrt {1 - x} \left (x + 1\right )^{2} - 60 \sqrt {1 - x} \left (x + 1\right ) + 60 \sqrt {1 - x}} & \text {otherwise} \end {cases} \]
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Leaf count of result is larger than twice the leaf count of optimal. 64 vs. \(2 (29) = 58\).
Time = 0.21 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.56 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=-\frac {2 \, \sqrt {-x^{2} + 1}}{5 \, {\left (x^{3} - 3 \, x^{2} + 3 \, x - 1\right )}} - \frac {\sqrt {-x^{2} + 1}}{15 \, {\left (x^{2} - 2 \, x + 1\right )}} + \frac {\sqrt {-x^{2} + 1}}{15 \, {\left (x - 1\right )}} \]
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none
Time = 0.34 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.54 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=\frac {{\left (x + 1\right )}^{\frac {3}{2}} {\left (x - 4\right )} \sqrt {-x + 1}}{15 \, {\left (x - 1\right )}^{3}} \]
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Time = 0.31 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.22 \[ \int \frac {\sqrt {1+x}}{(1-x)^{7/2}} \, dx=-\frac {\sqrt {1-x}\,\left (\frac {x\,\sqrt {x+1}}{5}+\frac {4\,\sqrt {x+1}}{15}-\frac {x^2\,\sqrt {x+1}}{15}\right )}{x^3-3\,x^2+3\,x-1} \]
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